AOC2022
By AjayKrP
advent-of-code-ocr
Convert Advent of Code ASCII art (by bsoyka)
| AOC2022 | advent-of-code-ocr | |
|---|---|---|
| 1 | 4 | |
| 0 | 12 | |
| - | - | |
| 10.0 | 10.0 | |
| over 1 year ago | over 1 year ago | |
| Python | Python | |
| - | MIT License |
The number of mentions indicates the total number of mentions that we've tracked plus the number of user suggested alternatives.
Stars - the number of stars that a project has on GitHub. Growth - month over month growth in stars.
Activity is a relative number indicating how actively a project is being developed. Recent commits have higher weight than older ones.
For example, an activity of 9.0 indicates that a project is amongst the top 10% of the most actively developed projects that we are tracking.
Stars - the number of stars that a project has on GitHub. Growth - month over month growth in stars.
Activity is a relative number indicating how actively a project is being developed. Recent commits have higher weight than older ones.
For example, an activity of 9.0 indicates that a project is amongst the top 10% of the most actively developed projects that we are tracking.
AOC2022
Posts with mentions or reviews of AOC2022.
We have used some of these posts to build our list of alternatives
and similar projects. The last one was on 2022-12-09.
advent-of-code-ocr
Posts with mentions or reviews of advent-of-code-ocr.
We have used some of these posts to build our list of alternatives
and similar projects. The last one was on 2022-12-09.
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[2022 Day 10 (Part 2)] A helpful Python module (again!)
In past years, I’ve created Advent of Code OCR for Python to convert ASCII letter art from these problems into plain text you can copy and paste.
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[2022 Day 10 (Part 2)] Today's puzzle not screenreader accessible
Python: advent-of-code-ocr module by /u/bsoyka (original post)
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-🎄- 2022 Day 10 Solutions -🎄-
The OCR is based on the number of active pixels for each column. The letter "E" has 6 lit pixels in the first column, 3 pixels in the 2nd and 3rd column and 2 pixels in the last column. By looking at the character list (thanks bsoyka on github!) I could craft a lookup table. The four integers will be shifted and added together to get a single integer. The 6,3,3,2 is transformed to 6<<0 + 3<<2 + 3<<4 + 2<<6 = 194 (the bits overlap, I know, but there are no collisions). The index of 194 in this magic list is 4. By adding 65 (ascii value of 'A') I can get the actual character with chr().
What are some alternatives?
When comparing AOC2022 and advent-of-code-ocr you can also consider the following projects:
AoC - my personal repo for the advent of code yearly challenge
adventofcode - my golang solution to adventofcode
adventofcode - Advent of Code solutions of 2015, 2016, 2017, 2018, 2019, 2020, 2021, 2022 and 2023 in Scala
LEARN__Coding-Practices-and-Datastructures - Daily Coding Practices, Data structures, otherwise testing and some stuff. (Some garbage/some stuff)
advent-of-code
advent-of-code - Solutions to Advent of Code in Elixir, Ruby
Advent-of-Code - Advent of Code
adventofcode - Advent of Code
aoc - advent of code
Advent-of-Code-2022 - My solutions for the 2022 Advent of Code in a mix of MATLAB and Python3
adventofcode - My solutions to the Advent of Code challenges
advent-of-code-2022
AOC2022 vs AoC
advent-of-code-ocr vs adventofcode
AOC2022 vs adventofcode
advent-of-code-ocr vs LEARN__Coding-Practices-and-Datastructures
AOC2022 vs advent-of-code
advent-of-code-ocr vs advent-of-code
AOC2022 vs Advent-of-Code
advent-of-code-ocr vs adventofcode
AOC2022 vs aoc
advent-of-code-ocr vs Advent-of-Code-2022
AOC2022 vs adventofcode
advent-of-code-ocr vs advent-of-code-2022