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AdventOfCode2021 | aoc | |
---|---|---|
12 | 22 | |
1 | 1 | |
- | - | |
2.6 | 9.0 | |
over 2 years ago | 4 months ago | |
Perl | Raku | |
- | MIT License |
Stars - the number of stars that a project has on GitHub. Growth - month over month growth in stars.
Activity is a relative number indicating how actively a project is being developed. Recent commits have higher weight than older ones.
For example, an activity of 9.0 indicates that a project is amongst the top 10% of the most actively developed projects that we are tracking.
AdventOfCode2021
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-🎄- 2021 Day 18 Solutions -🎄-
Full program on GitHub.
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-🎄- 2021 Day 15 Solutions -🎄-
Full program including code to deal with heaps, on GitHub.
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[2021 Day 11 (Part 2)] What input takes the most steps to synchronize?
Program I used for the above results
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-🎄- 2021 Day 8 Solutions -🎄-
See my solution on GitHub.
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Day 6 Proof of Correctness
Note also that you can solve this without a complexity dependency on n. Most solutions I have seen, including mine run in time O(tD), where t is the maximum value of a timer, and D the number of generation, requiring O(t) memory. (This is assuming we can do the required arithmetic operations in constant time, and each numbers require a fixed around of memory storage; if the number of fish gets huge, throw in an additional log n in the complexities, where n is the number of fish on the final day).
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-🎄- 2021 Day 6 Solutions -🎄-
Based on my matrix exponentiation solution, here is a closed-form solution:
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How do I read today's input ? Part 1
In my Perl solution of today (I assume, you mean 2021, Day 4), I read stuff in paragraph mode ($/ = "") which makes Perl split input on 2 or more newlines.
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2021 Day #4 (Part 1) [Native Python ONLY] - Conceptual Guidance?
I considered doing that for my (Perl) solution, but given the cards are small, that seemed overkill.
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-🎄- 2021 Day 4 Solutions -🎄-
Python implementation on GitHub
aoc
- -❄️- 2023 Day 10 Solutions -❄️-
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-❄️- 2023 Day 9 Solutions -❄️-
Full code at GitHub.
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-❄️- 2023 Day 7 Solutions -❄️-
Edit: you don't need to determine the type of hand, but you can directly compare the card counts. Second version @GitHub.
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-🎄- 2022 Day 13 Solutions -🎄-
New version @GitHub.
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-🎄- 2022 Day 12 Solutions -🎄-
So, a new version with a lot less almost-duplicate code @GitHub.
- -🎄- 2022 Day 2 Solutions -🎄-
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-🎄- 2022 Day 1 Solutions -🎄-
@GitHub
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-🎄- 2021 Day 21 Solutions -🎄-
Completed part 2, see GitHub. I couldn't really use the same `DiracDice` class and simply use another `Die`, but had to create a separate `DiracDice2` class.Basically, just keep track of the possible universe state and their counts, and try all possible combinations of die rolls. Keep playing until all universes have a winner.
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-🎄- 2021 Day 20 Solutions -🎄-
The rest is the same as my first attempt, but full code at GitHub.
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-🎄- 2021 Day 18 Solutions -🎄-
I spent way too much time on this, but I completed my original attempt with the proper object model, see GitHub
What are some alternatives?
Elixir - Elixir is a dynamic, functional language for building scalable and maintainable applications
rockstar - The Rockstar programming language specification
Advent-of-code - My solutions of adventofcode.com
advent-2021 - [Moved to: https://github.com/Crazytieguy/advent-of-code]
Advent_of_Code_2021_Solutions_Java - Personal AoC/2021 Solutions in Java
AdventOfCode - My Advent of Code solutions. I also upload videos of my solves: https://www.youtube.com/channel/UCuWLIm0l4sDpEe28t41WITA
adventofcode - Advent of Code solutions of 2015, 2016, 2017, 2018, 2019, 2020, 2021, 2022 and 2023 in Scala
adventofcode - Advent of code solutions
adventofcode - Advent of Code challenge solutions
advent-of-code-2021 - zig solutions to advent of code 2021
adventofcode - Solutions for problems from AdventOfCode.com
Advent-of-Code - Advent of Code