Custom set implementation

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  • haskell

    Exercism exercises in Haskell. (by exercism)

    I am working the Exercism Haskell Track and one of the questions asks for a custom set implementation. I studied some community solutions to see what other folks are doing, and came across something that I don't quite understand.


    A web site for converting haskell code into pointfree haskell code

    You can test out things like that at It takes a lambda with all the arguments present, like \ a b c -> f (g a b c), and it produces ((f .) .) . g.

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