adventofcode VS advent-of-code-ocr

Compare adventofcode vs advent-of-code-ocr and see what are their differences.

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adventofcode advent-of-code-ocr
1 4
2 12
- -
10.0 10.0
over 1 year ago over 1 year ago
Go Python
- MIT License
The number of mentions indicates the total number of mentions that we've tracked plus the number of user suggested alternatives.
Stars - the number of stars that a project has on GitHub. Growth - month over month growth in stars.
Activity is a relative number indicating how actively a project is being developed. Recent commits have higher weight than older ones.
For example, an activity of 9.0 indicates that a project is amongst the top 10% of the most actively developed projects that we are tracking.

adventofcode

Posts with mentions or reviews of adventofcode. We have used some of these posts to build our list of alternatives and similar projects. The last one was on 2022-12-09.

advent-of-code-ocr

Posts with mentions or reviews of advent-of-code-ocr. We have used some of these posts to build our list of alternatives and similar projects. The last one was on 2022-12-09.
  • [2022 Day 10 (Part 2)] A helpful Python module (again!)
    1 project | /r/adventofcode | 10 Dec 2022
    In past years, I’ve created Advent of Code OCR for Python to convert ASCII letter art from these problems into plain text you can copy and paste.
  • [2022 Day 10 (Part 2)] Today's puzzle not screenreader accessible
    4 projects | /r/adventofcode | 9 Dec 2022
    Python: advent-of-code-ocr module by /u/bsoyka (original post)
  • -🎄- 2022 Day 10 Solutions -🎄-
    201 projects | /r/adventofcode | 9 Dec 2022
    The OCR is based on the number of active pixels for each column. The letter "E" has 6 lit pixels in the first column, 3 pixels in the 2nd and 3rd column and 2 pixels in the last column. By looking at the character list (thanks bsoyka on github!) I could craft a lookup table. The four integers will be shifted and added together to get a single integer. The 6,3,3,2 is transformed to 6<<0 + 3<<2 + 3<<4 + 2<<6 = 194 (the bits overlap, I know, but there are no collisions). The index of 194 in this magic list is 4. By adding 65 (ascii value of 'A') I can get the actual character with chr().

What are some alternatives?

When comparing adventofcode and advent-of-code-ocr you can also consider the following projects:

aoc - advent of code

LEARN__Coding-Practices-and-Datastructures - Daily Coding Practices, Data structures, otherwise testing and some stuff. (Some garbage/some stuff)

advent_of_code - Solutions to programming puzzles on Advent of Code

advent-of-code - Solutions to Advent of Code in Elixir, Ruby

adventofcode - :christmas_tree: Advent of Code (2015-2023) in C#

adventofcode - Advent of Code

advent-of-code

Advent-of-Code-2022 - My solutions for the 2022 Advent of Code in a mix of MATLAB and Python3

advent-of-code - Advent of Code

advent-of-code-2022

adventofcode - Advent of Code solutions of 2015, 2016, 2017, 2018, 2019, 2020, 2021, 2022 and 2023 in Scala

advent-of-code-2022 - My solutions to Advent of Code 2022 problems