Hi guys is there any way of removing the all the other details from the terminal to display only the output.

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SurveyJS - Open-Source JSON Form Builder to Create Dynamic Forms Right in Your App
With SurveyJS form UI libraries, you can build and style forms in a fully-integrated drag & drop form builder, render them in your JS app, and store form submission data in any backend, inc. PHP, ASP.NET Core, and Node.js.
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InfluxDB - Power Real-Time Data Analytics at Scale
Get real-time insights from all types of time series data with InfluxDB. Ingest, query, and analyze billions of data points in real-time with unbounded cardinality.
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  • vscode-java-debug

    Java Debugger for Visual Studio Code.

  • You could set the java.debug.settings.console setting to internalConsole, to use the Debug Console instead of a terminal (which only shows the program output). The problem with that approach is that the Debug Console doesn't support user input. So if you want to have less verbose program output and and support for user input, I suggest you go upvote or comment microsoft/vscode-java-debug#906 to show that there's any demand for the feature.

  • SurveyJS

    Open-Source JSON Form Builder to Create Dynamic Forms Right in Your App. With SurveyJS form UI libraries, you can build and style forms in a fully-integrated drag & drop form builder, render them in your JS app, and store form submission data in any backend, inc. PHP, ASP.NET Core, and Node.js.

    SurveyJS logo
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