Why is the maybe monad transformer defined as MaybeT { runMaybeT :: m (Maybe a) } instead of MaybeT { runMaybeT :: Maybe (m a) } ?

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  • bifunctors

    Haskell 98 bifunctors, bifoldables and bitraversables

    • But it is possible to derive using a newtype of a tuple with its arguments reversed: Flip (,) s. If we get the (Biapplicative bi, Monoid b) => Applicative (Flip bi b) instance (issue). It will require a constraint to restrict m to have a representational argument because otherwise we cannot coerce through it.

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